And again, in the complete nonsensical quest of describing particle energies by many nines in 99.999999..% of the speed of light, the proper math falls down, 99.86% c is ~10 MeV, 60 MeV is about 99.996% c, but IT'S COMPLETELY MEANINGLESS!
Nevertheless...
Here's a handy online-tool to calculate the speed of a particle accellerated in a electric field (enter 60000 kV to get the values for the 60 MeV electron):
http://www.ou.edu/research/electron/bmz5364/calc-kv.html
Or calculate it yourself: E = E₀ / √( 1 - β²) with E₀ being the rest-energy of the particle (511 keV in the case of the electron) and β being the velocity relative to the speed of light.
At 99.86% of the speed of light, an electron will have a total (rest-mass + acquired energy by accelleration) energy of about 10 MeV:
(in python, energies in keV)
>>> 511. / math.sqrt( 1 - .9986 ** 2 )
9660.374008193809