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0 pointsempath758mo ago0 comments

He doesn't work with imaginary numbers, either. He treats complex numbers as matrices of rationals.

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Which is the same thing for all intents and purposes.

An ultrafinitist is still allowed to call that 'i'.

dhosek8mo ago

Still kind of freaked out that a Möbius transform can be expressed as a matrix multiplication.

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Which is the same thing for all intents and purposes.

An ultrafinitist is still allowed to call that 'i'.

dhosek8mo ago

Still kind of freaked out that a Möbius transform can be expressed as a matrix multiplication.

j / k navigate · click thread line to collapse