`for ((i = 0 ; i < max ; i++ )); do echo "$i"; done`
Here this is essentially a "while" loop, meaning it will keep executing the commands as long as we don't reach `exit 1`.
(; flock -n 9 || exit 1; # ... commands executed under lock ...; )
[~] 0 $ ( flock -n 9 || exit 1; echo in loop ; sleep 3 ; echo done working ; ) 9>~/tmp/mylock in loop done working [~] 0 $ (; flock -n 9 || exit 1; echo in loop ; sleep 3 ; echo done working ; ) 9>~/tmp/mylock -bash: syntax error near unexpected token `;' [~] 2 $
