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0 pointschuckadams2y ago0 comments

Or the fact that $FOO interprets as $(F)OO without the slightest warning. And of course if you're in a script line, you probably meant $$FOO..

Make certainly has some obscure variables, but of all the basic knowledge of Make you need to learn, $@ is near the top of the list (it's "target". an @ sign looks kind of like a bullseye. If you want to see it as visiting a dependency graph, it's the dependency you're currently "at").

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kbolino2y ago

Sure, if you use make enough, you likely remember the most important dollar-symbol stuff. But $@ is "all arguments (obeying quoting)" in bash, which is nothing like what it means in make.

chuckadamsOP2y ago

That of course becomes "$$@" in a Makefile recipe if you want bash's behavior and not make's... which is one of the reasons I tend to keep my shell scripts in separate files, and only grow a Makefile to wrap them later if I have to. These days I just have the directory of scripts and no Makefile. Even the rare times I do C, I prefer a script that recompiles everything and slapping ccache on top of it (but usually I'm dealing with an existing Makefile, and I just pray that it's not generated by automake)

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kbolino2y ago

Sure, if you use make enough, you likely remember the most important dollar-symbol stuff. But $@ is "all arguments (obeying quoting)" in bash, which is nothing like what it means in make.

chuckadamsOP2y ago

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