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0 pointsrezonant2y ago0 comments

It might predate HN but you are looking at the XY problem, not the YX problem. In this case, they are not commutative.

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4 comments · 2 top-level

dotancohen2y ago· 2 in thread

It seems that the YX problem is a derivative of the XY problem. In both cases we solve for X.

> seems

If you're actually unsure, then be sure. It's a derivative.

It's a play on words.

Yes the YX problem has a YX problem.

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