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0 pointsbonzini3y ago0 comments

Absolutely not, he needs to compute (63 - x) / 7, where x is computed from a 64-bit integers. There are no bigints involved.

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vintermann3y ago

Well, there are variable length integers involved, since it's as part of a way of representing variable length integers. But it seems you're right that x is just a regular machine int in this context, as an implementation detail. I misunderstood.

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0 pointsbonzini3y ago0 comments

Absolutely not, he needs to compute (63 - x) / 7, where x is computed from a 64-bit integers. There are no bigints involved.

0 comments

vintermann3y ago

Well, there are variable length integers involved, since it's as part of a way of representing variable length integers. But it seems you're right that x is just a regular machine int in this context, as an implementation detail. I misunderstood.

j / k navigate · click thread line to collapse