> Closest I can come is square minus the other two which gives:

Yep, you got it! That is the solution. There is a method to the madness. Given series S squares, F fibonaccis, P primes, with an op of minus, the convolution series

C = S op F op P = S op P op F

gives you 1 5 9 15 20 28... ( ps the third term is 9 and not 7 as stated in the original problem. In my defense, it was 7pm and I was drowsy when I posted that, so I must have looked at my watch, seen the 7 on the dial and then wrote 7 instead of 9. Apologies )