> What's the point in having headphones if you need to be in a Faraday cage to use them?
Surely it’s the opposite? They don’t work in a Faraday cage, because they’re streaming and need to be connected.
What is the use case for headphones that cut out every couple of seconds?
> Surely it’s the opposite? They don’t work in a Faraday cage, because they’re streaming and need to be connected.
In this case the broadcast source would be in the Faraday cage along with the listener.