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0 pointsoaiey4y ago0 comments

I completely get that. That is a very nice feature for building DSL or libraries with special needs. But it makes the overall language very dangerous.

Is this "operator" overloadable on each type in Python?

And that scares me a lot. I think I have to reevaluate my position towards Python.

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2 comments · 1 top-level

housecarpenter4y ago· 1 in thread

It's not really an operator. It's part of the syntax of string literals. "foo" "bar" is an alternative way of writing the string literal "foobar". If foo is not a string literal, foo "bar" is invalid syntax.

oaieyOP4y ago

Okay... So it is not a implicit operator. That is good. Some small reputation points are regained.

Thanks.

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