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0 pointsstefanos824y ago0 comments

...so it basically is `0 == ![]`, in other words, `[].length` which is `0`, thus becomes `0 == false` which returns `true` with loose comparison?

0 comments

Yep.

Because an array is an object which has a 'truthy' value '![]' evaluates as 'false'.

Simplifies to a statement similar to 'false == false'.

A little useless arcana for those interested.

Well, not so useless if your expecting '!someEmptyArray' to evaluate to 'true'. Use '!someEmptyArray.length' instead.

j / k navigate · click thread line to collapse

0 pointsstefanos824y ago0 comments

...so it basically is `0 == ![]`, in other words, `[].length` which is `0`, thus becomes `0 == false` which returns `true` with loose comparison?

Yep.

Because an array is an object which has a 'truthy' value '![]' evaluates as 'false'.

Simplifies to a statement similar to 'false == false'.

A little useless arcana for those interested.

Well, not so useless if your expecting '!someEmptyArray' to evaluate to 'true'. Use '!someEmptyArray.length' instead.

j / k navigate · click thread line to collapse