The last digit of any integer n^5 is n itself (opens in new tab)

(linkedin.com)

3 pointsjzox4y ago2 comments

2 comments

2 comments · 1 top-level

chmaynard4y ago· 1 in thread

Nonsense. How can the last digit of n^5 be n if n has more than one digit?

jzoxOP4y ago

Taken from the original post which is badly worded. It should read, the last digit of n^5 is always equal to the last digit of n

j / k navigate · click thread line to collapse