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0 pointskevincox5y ago0 comments

How does this work in C++ with operator overloading. Are they still the same? That would make for some interesting obfuscated code.

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3 comments · 2 top-level

jcelerier5y ago· 1 in thread

> How does this work in C++ with operator overloading.

you can't overload int::operator[](...)

I guess the question was whether the subscript operator is always assumed commutative in C++.

No, they're not. It works by: if either a or b in a[b] is a class/enumeration type, call a.operator[](b).

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