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0 pointsezy14y ago0 comments

Likewise for auto_ptr<T>, but he glosses over that.

0 comments

shasta14y ago

How do you figure? There isn't an implicit conversion from auto_ptr<T> to T *.

There isn't. There are two explicit methods to get raw pointer value with different semantics:

- get(): auto_ptr retains the ownership

- release(): auto_ptr loses the ownership

j / k navigate · click thread line to collapse

0 pointsezy14y ago0 comments

Likewise for auto_ptr<T>, but he glosses over that.

shasta14y ago

How do you figure? There isn't an implicit conversion from auto_ptr<T> to T *.

There isn't. There are two explicit methods to get raw pointer value with different semantics:

- get(): auto_ptr retains the ownership

- release(): auto_ptr loses the ownership

j / k navigate · click thread line to collapse