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ezy
15y ago
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Likewise for auto_ptr<T>, but he glosses over that.
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shasta
15y ago
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How do you figure? There isn't an implicit conversion from auto_ptr<T> to T *.
obiterdictum
15y ago
There isn't. There are two explicit methods to get raw pointer value with different semantics:
- get(): auto_ptr retains the ownership
- release(): auto_ptr loses the ownership
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