And if we are only looking at positive numbers in an infinite axis I’d need to borrow your generator for a test to approximate its midpoint (which obviously it doesn’t have), which I then weigh against the original number with the logic “if it’s larger than what I got, so is your other number. If it’s smaller so is the other number.” Now since the chance for my number being the middle of the three drawn is 1/3(only case I lose), that gives me 66% chance of winning that bet.