(just some fun little experiments I did last year https://github.com/jRimbault/DataStructures/blob/master/lib/..., there isn't any vtable, but it does show a string "class/struct" with all private fields, and methods for creating, managing those objects)
I have done this, 'fun' is not how I describe the result to colleagues
And every method of a Perl 5 object receives a $self scalar as its first argument ( see https://perldoc.perl.org/perlobj.html ).
In fact, Larry Wall specifically stated in the 11th "State of the Onion" speech that he "stole" Python's object system for Perl 5.
I remembered him saying this, so I went to find the transcript. However, I could not find a transcript of the actual speech. I did, though, find this perlmonks.org quote of Larry Wall (from that speech):
"I don't really know much about Python. I only stole its object system for Perl 5. I have since repented."
https://www.perlmonks.org/?node_id=1212836
So unless you mean Perl 5's "$self" is somehow "non-magic" (whatever you mean by that), I guess I don't understand what you mean when you say it has no "this" or "self".
Yeah, it has @_, and in the Perl object model, the first entry in the @_ array is a reference to the object, which is almost always called $self.
Anyway, what people name the reference doesn't matter. The point is that it functions like 'this' and 'self' do in other languages, and it is very much required in object methods (which differ from normal subs in that they are passed that first argument automatically).
Ed2: there's also Dylan, but again rather explicit: https://opendylan.org/documentation/intro-dylan/objects.html
As I understand it, rust is rather low on ceremony:
