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0 pointsjessriedel6y ago0 comments

What are you basing that on? (Edit:) From one of the papers released today:

> The ring is brighter in the south than the north. This can be explained by a combination of motion in the source and Doppler beaming. As a simple example we consider a luminous, optically thin ring... Then the approaching side of the ring is Doppler boosted, and the receding side is Doppler dimmed...This sense of rotation is consistent with the sense of rotation in ionized gas at arcsecond scales ..Notice that the asymmetry of the ring is consistent with the asymmetry inferred from 43 GHz observations of the brightness ratio between the north and south sides of the jet and counter-jet

https://iopscience.iop.org/article/10.3847/2041-8213/ab0f43

(Edit 2:) Ahh, I see your comment now says "did come out". I initially read it as "did not come out", which was either a misreading on my part (likely) or an earlier edit by you.

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typon6y ago

It's confirmed in the press conference by the scientists. They said its the Doppler beam effect

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pcmaffey6y ago

Are north and south in astronomy defined relative to Earth’s poles? What about “lateral” directions, since east and west are relative (no poles, ie. no east of earth)?

pi-squared6y ago

Using the right-hand rule: knowing the direction of spinning, if you point your thumb up and wrap the other four fingers in the direction of rotation, the thumb will be pointing North. Oposite of that is South. East can then be defined along the direction of spinning (eastward or counterclockwise looked from North, the way Earth is spinning) and West - opposite to that, clockwise looked from North, opposite the direction of rotation.

jessriedelOP6y ago

I don't know for sure how that's defined (I ctrl-f'd and it's not explained in the paper), but this says the "North" is to the right of the image, and from context it sounds like it's the north pole of the accretion disk, i.e., the direction of the rotation axis with the right-hand rule.

> The approaching side of the large-scale jet in M87 is oriented west–northwest (position angle $\mathrm{PA}\approx 288^\circ ;$ in Paper VI this is called ${\mathrm{PA}}_{\mathrm{FJ}}$), or to the right and slightly up in the image.

thro_away_n6y ago

In paper I, Figure 3, it says North is to the top of the image and East is to the left.

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0 pointsjessriedel6y ago0 comments

What are you basing that on? (Edit:) From one of the papers released today:

https://iopscience.iop.org/article/10.3847/2041-8213/ab0f43

(Edit 2:) Ahh, I see your comment now says "did come out". I initially read it as "did not come out", which was either a misreading on my part (likely) or an earlier edit by you.

0 comments

typon6y ago

It's confirmed in the press conference by the scientists. They said its the Doppler beam effect

1 more reply

pcmaffey6y ago

Are north and south in astronomy defined relative to Earth’s poles? What about “lateral” directions, since east and west are relative (no poles, ie. no east of earth)?

pi-squared6y ago

jessriedelOP6y ago

thro_away_n6y ago

In paper I, Figure 3, it says North is to the top of the image and East is to the left.

1 more reply

j / k navigate · click thread line to collapse