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0 pointsTheSpiceIsLife7y ago0 comments

I never finished school, so correct anything I've got wrong here.

Diesel has a specific energy of 48MJ/kg and weighs 0.832kg/L.

48MJ converts to 13.33kWh. My diesel tank will take 70L from nearly empty. I've never timed it, but it's definitely substantially quicker than 10 minutes to fill.

So I'm transferring about 776kWh in to my diesel tank in <10 mins.

70 * 0.832 * 13.33 = 776.33kWh

So it would take a 1MW charger three quarters of an hour to transfer the same amount of energy. <gasp>

Did I get any of that right?

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2 comments · 2 top-level

solarkraft7y ago

Seems about correct by energy going into your tank, but not energy actually going to the road later. Divide your result for that by 4 or 5.

kazinator7y ago

That's to say nothing of a caravan of trucks such as yours with full 70l tanks, barrelling down the freeway. If three such vehicles pass a given point per second, that's like 144 MW of power, I think!

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