My resignation letter is in ANSI C++

cperciva15y ago· 2 in thread

Is argc really a const in C++'s main? I can't imagine why it would be, given that argv++; argc--; is a very standard idiom in command-line argument processing.

AdamWynneOP15y ago

Seeing I wasn't using it, I thought I might hint to the optimiser that it could optimise it away. But now that you mention it, the argv should have been const char * const

cperciva15y ago

The optimizer is quite able to recognize that a variable is unused. :-)

In fact, if you compile that code with warnings turned on, you'll get a "variable is not used" warning -- which most style guides say should be silenced by adding the following line to the start of your function:

  (void)argc; /* UNUSED */

brettmjohnson15y ago· 1 in thread

  #include <stdio.h>
 
  int main (int argc, char **argv) {
    puts("Screw you guys! I'm going home.");	
  }

I'm thinking they were glad to see you go because you took an hour to do 60 seconds worth of work.

joezydeco15y ago

He could have put in some templating to make it easy for the next person to quit.

Spechal15y ago

Overkill

My resignation letter is in ANSI C++ (opens in new tab)

My resignation letter is in ANSI C++ (opens in new tab)

6 comments

6 comments